stpcpy - copy a string returning a pointer to its end
char *stpcpy(char *dest, const char *src);
The stpcpy() function copies the string pointed to by src
(including the terminating null byte ('\0')) to the array pointed to by
dest. The strings may not overlap, and the destination string
dest must be large enough to receive the copy.
stpcpy() returns a pointer to the end of the string dest
(that is, the address of the terminating null byte) rather than the beginning.
For an explanation of the terms used in this section, see attributes(7).
- Since glibc 2.10:
- _POSIX_C_SOURCE >= 200809L
- Before glibc 2.10:
This function was added to POSIX.1-2008. Before that, it was not part of the C
or POSIX.1 standards, nor customary on UNIX systems. It first appeared at
least as early as 1986, in the Lattice C AmigaDOS compiler, then in the GNU
fileutils and GNU textutils in 1989, and in the GNU C library by 1992. It is
also present on the BSDs.
This function may overrun the buffer dest.
For example, this program uses stpcpy() to concatenate foo and
bar to produce foobar, which it then prints.
char *to = buffer;
to = stpcpy(to, "foo");
to = stpcpy(to, "bar");
This page is part of release 5.10 of the Linux man-pages project. A
description of the project, information about reporting bugs, and the latest
version of this page, can be found at https://www.kernel.org/doc/man-pages/.